How to make calculations on hexadecimal numbers with awk? - Stack Overflow

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How to make calculations on hexadecimal numbers with awk?

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I have a file containing a list of hexadecimal numbers, as 0x12345678 one per line. I want to make a calculation on them. For this, I thought of using awk. But if printing an hexadecimal number with awk is easy with the printf function, I haven't find a way to interpret the hexadecimal input other than as text (or 0, conversion to integer stops on the x). awk '{ print $1; }'                     // 0x12345678 awk '{ printf("%x\n", $1)}'             // 0 awk '{ printf("%x\n", $1+1)}'           // 1                 // DarkDust answer awk '{ printf("%s: %x\n", $1, $1)}'     // 0x12345678: 0 Is it possible to print, e.g. the value +1? awk '{ printf(%x\n", ??????)}'          // 0x12345679 Edit: One liners on other languages welcomed! (if reasonable length ;-) ) awk hex link|edit edited Sep 10 '10 at 8:29 asked Sep 10 '10 at 8:15 Didier Trosset 11.5k21639 83% accept rate

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In the original nawk and mawk implementations the hexadecimal (and octal) numbers are recognised.gawk (which I guess you are using) has the feature/bug of not doing this. It has a command line switch to get the behaviour you want: --non-decimal-data. echo 0x12345678 | mawk '{ printf "%s: %x\n", $1, $1 }' 0x12345678: 12345678 echo 0x12345678 | gawk '{ printf "%s: %x\n", $1, $1 }' 0x12345678: 0 echo 0x12345678 | gawk --non-decimal-data '{ printf "%s: %x\n", $1, $1 }' 0x12345678: 12345678 link|edit answered Sep 10 '10 at 8:36 schot 4,3991931

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up vote1down vote	gawk has the strtonum function: % echo 0x12345678 | gawk '{ printf "%s: %x - %x\n", $1, $1, strtonum($1) }' 0x12345678: 0 - 12345678 link|edit answered Sep 10 '10 at 10:46 glenn jackman 22.4k1132
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up vote0down vote	You can convert the string into a number, simply by doing $1 + 0. AWK automagically converts a string to a number as needed. So you can do: awk '{ printf "%X\n", $1+1; }' or if you want 0x1234 notation: awk '{ printf "0x%X\n", $1+1; }' link|edit answered Sep 10 '10 at 8:23 DarkDust 27.1k22051
	This does not work on my Linux system (debian): It prints 1. My guess is that awk tries to interpret the value as decimal and stops right after the 0, on the x, ignoring that 0x is an hexadecimal notation prefix. – Didier Trosset Sep 10 '10 at 8:27 Was this post useful to you?

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