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snutz411 · 11-01-2005, 04:33 PM

is there a way i can write a shell script that will be able to increment in hex?

i.e. i was to get all the values from 000 to FFF

Dark_Helmet · 11-01-2005, 04:47 PM

Incrementing by one in hex is the same as incrementing by one in any other number base

My suggestion: Do the increment like normal, and manually convert to hex format when you need to display or compare it to a hex value.

For instance:

Code:

#!/bin/bash

for number in $( seq 1 255 )
do
  hex_representation=$( printf "%X" ${number} )
  echo "${number}: ${hex_representation}"
done

If you're script is given the value of the number to increment in hex notation, you can also use printf to convert it to decimal for you:

Code:

number=$( printf "%d" 0x${hex_representation}" )

I'm not claiming that any of this is efficient by any means. Nor am I saying it will solve all your problems

But it should give you a start.

solveit · 11-01-2005, 05:54 PM

Try this :

Code:

i=0

while [ $i  -lt  4096 ]
do
   x=`printf "%04X\n"  $i`
   echo $x
   i=`expr $i + 1`
done

11-01-2005, 04:33 PM	#1
snutz411 Member Registered: Mar 2004 Distribution: Slackware 10.0 Posts: 55 Rep:	increment in hex [Log in to get rid of this advertisement] is there a way i can write a shell script that will be able to increment in hex? i.e. i was to get all the values from 000 to FFF

11-01-2005, 04:47 PM	#2
Dark_Helmet Senior Member Registered: Jan 2003 Distribution: Debian 6.0.3, Ubuntu Server 10.04 Posts: 2,786 Rep:	Incrementing by one in hex is the same as incrementing by one in any other number base My suggestion: Do the increment like normal, and manually convert to hex format when you need to display or compare it to a hex value. For instance: Code: #!/bin/bash for number in $( seq 1 255 ) do hex_representation=$( printf "%X" ${number} ) echo "${number}: ${hex_representation}" done If you're script is given the value of the number to increment in hex notation, you can also use printf to convert it to decimal for you: Code: number=$( printf "%d" 0x${hex_representation}" ) I'm not claiming that any of this is efficient by any means. Nor am I saying it will solve all your problems But it should give you a start.

11-01-2005, 05:54 PM	#3
solveit Member Registered: Jan 2005 Posts: 83 Rep:	Try this : Code: i=0 while [ $i -lt 4096 ] do x=`printf "%04X\n" $i` echo $x i=`expr $i + 1` done

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